## Algebra 1

We know that 3x-4=y. Thus, in the first equation, wherever we see y, we will substitute 3x-4, and then we will solve: $-2x +5(3x-4) = 19 \\\\ -2x + 15x -20 =19 \\\\ 13x = 39 \\\\ x=3$ We now plug x=3 back in: $y=3(3)-4=5$