Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Lesson Check: 1

Answer

$(25\frac{5}{11},6\frac{4}{11})$

Work Step by Step

Substitute 4y for x in the 2nd equation and solve for y. $3x-y=70$ $3(4y)-y=70$ $12y-y=70$ $11y=70$ $11y\div11=70\div11$ $y=6\frac{4}{11}$ Substitute $6\frac{4}{11}$ for y in the first equation. $4y=x$ $4(6\frac{4}{11})=x$ $25\frac{5}{11}=x$ Substitute the values into each equation to check the answer. $4y=x$ $4(6\frac{4}{11})=25\frac{5}{11}$ $25\frac{5}{11}=25\frac{5}{11}\checkmark$ $3x-y=70$ $3(25\frac{5}{11})-6\frac{4}{11}=70$ $76\frac{4}{11}-6\frac{4}{11}=70$ $70=70\checkmark$
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