## Algebra 1

(-7, 6) and (-4, 11) are given $m = (6-11)/(-7--4)$ $m= -5/-3$ $m = 5/3$ $y=mx+b$ $11 = 5/3 *-4 + b$ $11 = -20/3 + b$ $11+20/3 = -20/3 + b + 20/3$ $53/3 = b$ $y = 5/3*x + 53/3$ Let x = 0: $y = 5/3*0 + 53/3$ $y = 53/3$ Let y = 0 $y = 5/3*x + 53/3$ $0 = 5/3*x + 53/3$ $0*3= 3*(5/3*x + 53/3)$ $0 = 5x + 53$ $0-53 = 5x +53 -53$ $-53 = 5x$ $-53/5 = 5x/5$ $-53/5 = x$