Algebra 1

x-intercept: 4 y-intercept: 3 $3x + 4y = 12$
(4,0) and (0,3) are given $m = (3-0)/(0-4)$ $m = -3/4$ $y = mx+b$ $0 = -3/4*4 + b$ $0 = -3 + b$ $0+3 = -3 + b + 3$ $3 = b$ $y = -3/4*x + 3$ $4 *y = 4* (-3/4x + 3)$ $4y = -3x + 12$ $4y +3x = -3x + 12 + 3x$ $3x + 4y = 12$