## Algebra 1

$x>3$ or $x\leq-1$
Solve the first part, $3x+1>10$ and subtract 1 from both sides. After doing that, divide both sides by 3. You will end up with $x>3$. To solve the second part, $5x+3\leq-2$, subtract 3 from both sides. Then divide both sides by 5. You will end up with $x\leq-1$. Proceed to graph $x>3$ or $x\leq-1$ on a number line.