## Algebra 1

$y-4 = -5/8*(x+3)$ $y = -5/8*x + 17/8$
given: (5, -1) and (-3, 4) $y-y_{1} = m*(x-x_{1})$ $m = (-1-4)/(5--3)$ $m = -5/8$ $y-4 = -5/8*(x+3)$ $y-4 = -5/8*(x+3)$ $y-4 = -5/8*x-15/8$ $y-4+4 = -5/8*x-15/8+4$ $y = -5/8*x + 17/8$