Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 5 - Linear Functions - 5-5 Standard Form - Lesson Check: 5

Answer

$10x + 25y = 285$ (26, 1), (21, 3), and (16, 5) are three possible options.

Work Step by Step

The possible options are 10 and 25 gift cards, with a limit of 285 to spend. The intercepts have decimals, so we can't use the intercepts as possible values for the quantities of gift cards purchased. Allow the following: y=1, y =3, and y=5 y=1 $10x + 25(1) = 285$ $10x + 25 = 285$ $10x +25 (-25)= 285 (-25)$ $10x = 260$ $10x (*1/10) = 260 (*1/10)$ $ x = 26$ y=3 $10x + 25(3) = 285$ $10x + 75 = 285$ $10x +75 (-75)= 285 (-75)$ $10x = 210$ $10x (*1/10) = 210 (*1/10)$ $ x = 21$ y=5 $10x + 25(5) = 285$ $10x + 125 = 285$ $10x +125 (-125)= 285 (-125)$ $10x = 160$ $10x (*1/10) = 160 (*1/10)$ $ x = 16$
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