## Algebra 1

$y-3 = \frac{4}{3} *(x-1)$
The line goes through (1,3) and (-2, -1). $m = \frac{3- -1}{1- - 2}$ $m = \frac{4}{3}$ $y-y_{1} = m *(x-x_{1})$ $y-3 = \frac{4}{3} *(x-1)$