Chapter 5 - Linear Functions - 5-4 Point-Slope Form - Practice and Problem-Solving Exercises - Page 316: 15

Please see the graph.

$y-2 = 4/9*(x-3)$ One point on this line is (3,2) (per the formula for point-slope equation). Now, let $x=0$ $y-2 = 4/9*(0-3)$ $y-2 = 4/9*-3$ $y-2 = -12/9$ $y-2 = -4/3$ $y=2/3$ We now have the point (0,2/3). The graphs shows the line that goes through both points.