Algebra 1

y=-$\frac{1}{4}$x+$\frac{9}{4}$
Slope-intercept form is written as y=mx+b. m=$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$, and it's given that $x_{1}$=-3, $x_{2}$=1, $y_{1}$=3, $y_{2}$=2, we can solve for m by plugging in the givens into the slope equation. Therefore, m=$\frac{2-3}{1-(-3)}$=$\frac{-1}{4}$=-$\frac{1}{4}$. Now we know the y=(-$\frac{1}{4}$)x+b=-$\frac{1}{4}$x+b, and we can solve for b by plugging in one of the two points, in this case we'll plug in the point (1,2) 2=(-$\frac{1}{4}$)(1)+b, and when we add $\frac{1}{4}$ to each side, we get b=$\frac{9}{4}$ Therefore, y=-$\frac{1}{4}$x+$\frac{9}{4}$