## Algebra 1

Slope-intercept form is written as y=mx+b. m=$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$, and it's given that $x_{1}$=0, $x_{2}$=2, $y_{1}$=3, $y_{2}$=5, we can solve for m by plugging in the givens into the slope equation. Therefore, m=$\frac{5-3}{2-0}$=$\frac{2}{2}$=1. Now we know the y=(1)x+b=x+b, and we can solve for b by plugging in one of the two points, in this case we'll plug in the point (0,3) 3=0+b, so 3=b. Therefore, y=x+3