## Algebra 1

f(x) = 8x - 3 The domain is {-$\frac{1}{2}$,$\frac{1}{4}$,$\frac{3}{4}$,$\frac{1}{8}$}. The domain gives the x value so we substitute the x into the equation f(x) = 8x - 3 x= -$\frac{1}{2}$ f(-$\frac{1}{2}$) = 8(-$\frac{1}{2}$) - 3 f(-$\frac{1}{2}$) = -7 x= $\frac{1}{4}$ f($\frac{1}{4}$) = 8($\frac{1}{4}$) - 3 f($\frac{1}{4}$) = -1 x= $\frac{3}{4}$ f($\frac{3}{4}$) = 8($\frac{3}{4}$) - 3 f($\frac{3}{4}$) = 3 x= $\frac{1}{8}$ f($\frac{1}{8}$) = 8($\frac{1}{8}$) - 3 f($\frac{1}{8}$) = -2 Therefore we get the range to be {-7, -2, -1, 3}.