Answer
The range is {0, 0.04 , 1.44 , 16}
Work Step by Step
h(x) = $x^{2}$
The domain is {-1.2,0,0.2,1.2,4}.
The domain gives the x value so we substitute the x into the equation h(x) = $x^{2}$
x=-1.2
h(-1.2) = $(-1.2)^{2}$
h(-1.2) = 1.44
x=0
h(0) = $(0)^{2}$
h(0) = 0
x=0.2
h(0.2) = $(0.2)^{2}$
h(0.2) = 0.04
x=1.2
h(1.2) = $(1.2)^{2}$
h(1.2) = 1.44
x=4
h(4) = $(4)^{2}$
h(4) = 16
Therefore we get the range to be {0, 0.04 , 1.44 , 16}
