Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 4 - An Introduction to Functions - 4-6 Formalizing Relations and Functions - Practice and Problem-Solving Exercises: 20

Answer

The range is {0, 0.04 , 1.44 , 16}

Work Step by Step

h(x) = $x^{2}$ The domain is {-1.2,0,0.2,1.2,4}. The domain gives the x value so we substitute the x into the equation h(x) = $x^{2}$ x=-1.2 h(-1.2) = $(-1.2)^{2}$ h(-1.2) = 1.44 x=0 h(0) = $(0)^{2}$ h(0) = 0 x=0.2 h(0.2) = $(0.2)^{2}$ h(0.2) = 0.04 x=1.2 h(1.2) = $(1.2)^{2}$ h(1.2) = 1.44 x=4 h(4) = $(4)^{2}$ h(4) = 16 Therefore we get the range to be {0, 0.04 , 1.44 , 16}
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