## Algebra 1

A= w$\times$(3w-2) The area of the rectangle when its width is 2 ft is 8 $ft^{2}$
The formula for the Area of a rectangle is A= w$\times$l and in this scenario, the length is 2 minus 3 times the width this l= 3w-2, therefore substituting 3w-2 for l we get A= w$\times$(3w-2) For the question, What is the area of the rectangle when its width is 2 ft? We substitute 2 for w. w=2 A= w$\times$(3w-2) A= (2)$\times$(3(2)-2) A= 8 $ft^{2}$