#### Answer

A= w$\times$(3w-2)
The area of the rectangle when its width is 2 ft is 8 $ft^{2}$

#### Work Step by Step

The formula for the Area of a rectangle is
A= w$\times$l
and in this scenario, the length is 2 minus 3 times the width this l= 3w-2,
therefore substituting 3w-2 for l we get
A= w$\times$(3w-2)
For the question, What is the area of the rectangle when its width is 2 ft? We substitute 2 for w.
w=2
A= w$\times$(3w-2)
A= (2)$\times$(3(2)-2)
A= 8 $ft^{2}$