Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 4 - An Introduction to Functions - 4-5 Writing a Function Rule - Practice and Problem-Solving Exercises: 20

Answer

V= $\pi r^{2}$ (4r+3) The volume of the cylinder when it has a radius of 2 in. is 138.16 $in^{3}$

Work Step by Step

The formula for the volume of a cylinder is V= $\pi r^{2}$ h and in this scenario, the height is 3 plus 4 times the radius this h= 4r+3, therefore substituting 4r+3 for h we get V= $\pi r^{2}$ (4r+3) For the question, What is the volume of the cylinder when it has a radius of 2 in.? We substitute 2 for r. r=2 V= $\pi r^{2}$ (4r+3) V= (3.14) $(2)^{2}$ (4(2)+3) V= 138.16 $in^{3}$
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