Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 4 - An Introduction to Functions - 4-3 Patterns and Nonlinear Functions - Practice and Problem-Solving Exercises: 20

Answer

A=rx^{y}2 (4-\pi)

Work Step by Step

They area of the region can be found by subtracting the area of the square minus the area of the circle. Area of square = Length \times width = (2r)x^{y}2 Area of circle = \pirx^{y}2 Area of region= Area of square-Area of circle A= (2r)x^{y}2 - \pirx^{y}2 -Distribute the square to the 2 and r A=4rx^{y}2 - \pirx^{y}2 - rx^{y}2 is common so it is to be factored out A= rx^{y}2 (4-\pi)
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