## Algebra 1

$d\lt-3$
$8d+2\lt5d-7\longrightarrow$ subtract 5d from each side $8d+2-5d\lt5d-7-5d\longrightarrow$ subtract $3d+2\lt-7\longrightarrow$ subtract 2 from each side $3d+2-2\lt-7-2\longrightarrow$ subtract $3d\lt-9\longrightarrow$ divide each side by 3 $3d\div3\lt-9\div3\longrightarrow$ divide $d\lt-3$ Since -3 is not included in the solution set, the endpoint of the graph is an open circle.