## Algebra 1

Find the solution for $m-\frac{1}{2}\lt\frac{3}{8}$ to determine whether it is equivalent to $m\lt\frac{7}{8}$. $m-\frac{1}{2}\lt\frac{3}{8}\longrightarrow$ add $\frac{1}{2}$ to each side $m-\frac{1}{2}+\frac{1}{2}\lt\frac{3}{8}+\frac{1}{2}\longrightarrow$ convert to a like fraction $m-\frac{1}{2}+\frac{1}{2}\lt\frac{3}{8}+\frac{4}{8}\longrightarrow$ add $m\lt\frac{7}{8}$ Since the solutions for m are the same, the two expressions are equivalent.