#### Answer

equivalent

#### Work Step by Step

Find the solution for $m-\frac{1}{2}\lt\frac{3}{8}$ to determine whether it is equivalent to $m\lt\frac{7}{8}$.
$m-\frac{1}{2}\lt\frac{3}{8}\longrightarrow$ add $\frac{1}{2}$ to each side
$m-\frac{1}{2}+\frac{1}{2}\lt\frac{3}{8}+\frac{1}{2}\longrightarrow$ convert to a like fraction
$m-\frac{1}{2}+\frac{1}{2}\lt\frac{3}{8}+\frac{4}{8}\longrightarrow$ add
$m\lt\frac{7}{8}$
Since the solutions for m are the same, the two expressions are equivalent.