Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-8 Proportions and Similar Figures - Lesson Check - Page 133: 2


225 km

Work Step by Step

Setting up a proportion is the first step to solving this problem: $\frac{\text{distance of the two towns on map}}{\text{actual distance of the two towns}}$= $\frac{\text{1 cm}}{\text{75 km}}$ 1 cm : 75 km was already given as the scale, so half of the proportion was immediately filled out. Now, substitute the given distance of the two towns on the map: $\frac{\text{3 cm}}{x}$= $\frac{\text{1 cm}}{\text{75 km}}$ Cross Products Property: 3(75)=1$x$ Multiply the left side of the equation and then divide by 1 on each side of the equation: $\frac{225}{1}$=225 The actual distance between the two towns is 225 km.
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