Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-7 Solving Proportions - Practice and Problem-Solving Exercises - Page 128: 39


$2047\frac{3}{7}$ kilowatt hours

Work Step by Step

Assume that h is the number of kilowatt hours. $\frac{1}{0.07}=\frac{h}{143.32}$ cross multiply $0.07h=143.32$ divide both sides by 0.07 $0.07h\div0.07=143.32\div0.07$ simplify $h=2047\frac{3}{7}$
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