## Algebra 1

$2047\frac{3}{7}$ kilowatt hours
Assume that h is the number of kilowatt hours. $\frac{1}{0.07}=\frac{h}{143.32}$ cross multiply $0.07h=143.32$ divide both sides by 0.07 $0.07h\div0.07=143.32\div0.07$ simplify $h=2047\frac{3}{7}$