Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-7 Solving Proportions - Practice and Problem-Solving Exercises - Page 128: 53



Work Step by Step

5x(x^2-7)= 5(x^3+5) (Using cross product rule) 5x^3-35x=5x^3+25 (Using distributive property , simplify paranthesis) Subtract 5 x^3 on both sides, 5x^3-35x-5x^3=5x^3+25-5x^3 -35x=25 Dividing both sides by -35, we get x=-25/35 hence x=-5/7.
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