Algebra 1

$x = 14$
Make the three consecutive numbers $x, x+1$, and $x+2.$ $x + (x+1) + (x+2) = 45$ Combine like terms to get: $3x + 3 = 45$ Subtract $3$ from each side. $3x+3-3= 45-3 = 42$ $3x = 42$ $x = 14$