## Algebra 1

$253.75in^{2}; 286.75in^{2}$
Since the original values are whole numbers to find the minimum area we will go down a half inch on each number and for the maximum area we will go up a half inch on each number. Minimum: $17.5in\times14.5in=253.75in^{2}$ Maximum: $18.5in\times15.5in=286.75in^{2}$