Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-10 Change Expressed as a Percent - Practice and Problem-Solving Exercises - Page 149: 32


$253.75in^{2}; 286.75in^{2}$

Work Step by Step

Since the original values are whole numbers to find the minimum area we will go down a half inch on each number and for the maximum area we will go up a half inch on each number. Minimum: $17.5in\times14.5in=253.75in^{2}$ Maximum: $18.5in\times15.5in=286.75in^{2}$
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