#### Answer

$\frac{3}{5}$

#### Work Step by Step

P(odd)=$\frac{5}{10}$-there are 5 odd numbers out of 10
P(multiple of 3)=$\frac{3}{10}$ -three multiples of 3-
P(odd or multiple of 3)=P(odd)+P(multiple of 3)+Probability events will occur
P(odd or multiple of 3)-$\frac{5}{10}$ +$\frac{3}{10}$-$\frac{2}{10}$
P(odd or multiple of 3-$\frac{6}{10}$=$\frac{3}{5}$