## Algebra 1

Published by Prentice Hall

# Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises: 11

#### Answer

$\frac{1}{2}$

#### Work Step by Step

Looking at the spinner, there is one 3 and five red sections, out of 10 sections. However, we must take into account that the 3 is a red section. P(3 or red) = P(3) + P(red) - P(3 and red) = $\frac{1}{10}+\frac{5}{10} - \frac{1}{10} = \frac{5}{10} = \frac{1}{2}$

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