Chapter 12 - Data Analysis and Probability - 12-7 Thoretical and Experimental Probability - Practice and Problem-Solving Exercises - Page 761: 21

$\frac{1}{3}$

P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ There are 6 possible outcomes because there are 6 total areas. There are 2 numbers greater than 4(5,6) so 2 is the number of favorable outcomes. P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ P(greater than 4)=$\frac{2}{6}$ -simplify- P(greater than 4)=$\frac{1}{3}$