## Algebra 1

$\frac{2}{3}$
Use p(not less than 3)=$\frac{numeroffavorableoutcomes}{numberofpossible outcomes}$ There are 6 possible outcomes. There are 4 favorable outcomes:3,4,5 and 6. Plug into the fraction: p(not less than3)=$\frac{favorableoutcomes}{possibleoutcomes}$ p(not less than 3)=$\frac{4}{6}$ p(not less than 3)=$\frac{2}{3}$