Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 755: 53



Work Step by Step

Use the formula for combination: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$ because arrangement or order do not matter.Plug in 8 for N and 3 for R: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$ $_{8}$C$_{3}$=$\frac{8!}{8!(8-3)!}$ -simplify like terms- $_{8}$C$_{3}$=$\frac{8!}{3! (5!)}$ -write using factorial- $_{8}$C$_{3}$=$\frac{8*7*6*5*4*3*2*1}{(3*2*1)(5*4*3*2*1)}$ -simplify- $_{8}$C$_{3}$=56
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