## Algebra 1

x $\geq$ -3
You have the inequality: 3(x-2) $\leq$ 6x+3 and you have to find the solution: 3(x-2) $\leq$ 6x+3 -distribute- 3x-6 $\leq$ 6x+3 -add 6 to both sides- 3x $\leq$ 6x+9 -subtract 6x from both sides- -3x $\leq$ 9 -divide both sides and then reverse the sign because you are dividing by a negative number- x $\geq$ -3