Answer
x $\geq$ -3
Work Step by Step
You have the inequality: 3(x-2) $\leq$ 6x+3 and you have to find the solution:
3(x-2) $\leq$ 6x+3 -distribute-
3x-6 $\leq$ 6x+3 -add 6 to both sides-
3x $\leq$ 6x+9 -subtract 6x from both sides-
-3x $\leq$ 9 -divide both sides and then reverse the sign because you are dividing by a negative number-
x $\geq$ -3
