## Algebra 1

a$\gt$1
Initial problem: 4-3a $\lt$ 3a-2.You have to solve for a so: 4 - 3a$\lt$ 3a - 2 -subtract 4 from both sides- -3a$\lt$3a-6 -subtract 3a from both sides- -6a$\lt$-6 -divide each side by -6 and since you are dividing by a negative number, you have to reverse the sign- a$\gt$1.