## Algebra 1

$y=20*.5^x$ $y=.5*4^x$ $20*.5^x=.5*4^x$ $40*.5^x=4^x$ $40*.5^x=(8/2)^x$ $40*.5^x=8^x*(1/2)^x$ $40*.5^x=8^x*.5^x$ $40=8^x$ When $x=1.774$, this is a true statement. Thus, the two integers are 1 and 2.