Answer
$\frac{q^6}{p^5}$
Work Step by Step
$\frac{m^2p^{-3}q^4}{m^2p^2q^{-2}}$
Looking at the expression, we see that $m^2$ is a common factor and can cancel out of the numerator and denominator. We will then make all exponents positive, moving accordingly:
$\frac{m^2p^{-3}q^4}{m^2p^2q^{-2}}$ = $\frac{p^{-3}q^4}{p^2q^{-2}}$ = $\frac{q^{4+2}}{p^{2+3}}$ = $\frac{q^6}{p^5}$
