Algebra 1

$r=-2/3$ or $r=-5$
$6r^2+20=-34r$ $6r^2+34r+20$ $20*6=120$ $30*4=120, 30+4=34$ $6r^2+30r+4r+20$ $6r(r+5)+4(r+5)$ $(6r+4)(r+5)$ $6r+4=0$ $6r=-4$ $r=-4/6$ simplifies to $r=-2/3$ Alternatively $r+5=0$ $r=-5$