Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - Cumulative Test Prep - Short Response - Page 710: 29



Work Step by Step

As we are given that $\dfrac{x^2+3x-18}{6x+36}$ $\dfrac{x^2+3x-18}{6x+36}=\dfrac{x^2-3x+6x-18}{6(x+6)}$ $=\dfrac{x(x-3)+6(x-3)}{6(x+6)}$ $=\dfrac{(x-3)(x+6)}{6(x+6)}$ After simplifications, we get: $=\dfrac{(x-3)}{6}$
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