Answer
$\dfrac{(x-3)}{6}$
Work Step by Step
As we are given that $\dfrac{x^2+3x-18}{6x+36}$
$\dfrac{x^2+3x-18}{6x+36}=\dfrac{x^2-3x+6x-18}{6(x+6)}$
$=\dfrac{x(x-3)+6(x-3)}{6(x+6)}$
$=\dfrac{(x-3)(x+6)}{6(x+6)}$
After simplifications, we get: $=\dfrac{(x-3)}{6}$
