Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - Cumulative Test Prep - Extended Response - Page 710: 30


(a) $F=\dfrac {9}{5}C+32$ (b) $95 ^\circ F$

Work Step by Step

(a) As we are given that $C=\dfrac {5}{9}(F-32)$ $9C=5(F-32)$ [ Cross multiplication ] $\dfrac {9}{5}C=(F-32)$ $F-32=\dfrac {9}{5}C$ $F=32+\dfrac {9}{5}C$ or, $F=\dfrac {9}{5}C+32$ (b) From part (a), we have : $F=\dfrac {9}{5}C+32$ Thus, at $C=35$, the equation becomes $F=\dfrac {9}{5}(35)+32$ $F=63+32=95 ^\circ F$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.