Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 670: 42

Answer

$-16c^2-20c-25$

Work Step by Step

Re-arranging the order of the terms and leaving space for missing terms, the given is equivalent to $$ (64c^3+0c^2+0c-125)÷(-4c+5) .$$ Using the long division method shown below, then $$\begin{aligned} & (64c^3-125)÷(-4c+5) \\&= -16c^2-20c-25+\frac{\color{red}{0}}{\color{blue}{-4c+5}} \\&= -16c^2-20c-25 .\end{aligned} $$
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