Answer
$2x^2+3x+\frac{2}{3}-\frac{8}{3(3x-5)}$
Work Step by Step
Re-arranging the order of the terms, the given is equivalent to
$$
(6x^3-x^2-13x-6)÷(3x-5)
.$$
Using the long division method shown below, then
$$\begin{aligned}
&
(6x^3-x^2-13x-6)÷(3x-5)
\\&=
2x^2+3x+\frac{2}{3}-\frac{8}{3(3x-5)}
.\end{aligned}
$$
