Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 669: 19



Work Step by Step

In order to match the first term of the dividend, $-4q^2$, the divisor $2q+1$ must be multiplied by $-2q$. The $-2q$ will go on top of your division sign. $$(-2q)(2q+1) = -4q^2-2q$$ Then, subtract this from the first two terms of the dividend. $$(-4q^2-22q+12)-(-4q^2-2q)=-20q$$ Bring down the next term of the dividend. $$-20q+12$$ Multiply the divisor by $-10$ to match this. The $-10$ will follow the $-2q$ on top of your division sign. $$(-10)(2q+1) = -20q-10$$ Subtract this from the $-20q+12$ $$(-20q+12)-(-20q-10) = 22$$ Since your remainder is $22$, you can add $\frac{22}{2q+1}$ to your answer. $$-2q-10+\frac{22}{2q+1}$$
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