## Algebra 1

Yes, it is the same. When we factor the numerator, it becomes $\frac{x^2 -9}{x+3} = \frac{(x-3)(x+3)}{x+3}$ Now we can see that $x+3$ cancel out, leaving us with $x-3$ as our final answer.
Yes, it is the same. When we factor the numerator, it becomes $\frac{x^2 -9}{x+3} = \frac{(x-3)(x+3)}{x+3}$ Now we can see that $x+3$ cancel out, leaving us with $x-3$ as our final answer.