## Algebra 1

$a\ne -1$ $\frac{a+1}{5}$
To find excluded values, we look at the denominator and find the values that would make it zero. To do this, we can set the denominator equal to zero and solve. $5a + 5 = 0$ $5a +5=0 -5$ Subtract 5 from each side $\frac{5}{5}a = \frac{-5}{5}$ Divide each side by 5 $a = -1$ Simplify Therefore, $a\ne-1$, therefore -1 is our excluded value. To simplify the expression, we need to factor the numerator and denominator. $\frac{a^2+2a+1}{5a+5} = \frac{(a+1)(a+1)}{5(a+1)}$ Now we can divide out the common factor of $(a+1)$ $\frac{(a+1)(a+1)}{5(a+1)} = \frac{a+1}{5}$