Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Mid-Chapter Quiz: 25

Answer

$3\sqrt{2}-4\sqrt{3}$

Work Step by Step

Using the distribution property, $\sqrt{3}(\sqrt{6}-4)= \sqrt{3} \ast \sqrt{6}-\sqrt{3}\ast 4$. Since $6=3\ast2$, $\sqrt{3}(\sqrt{6}-4)=\sqrt{3}\ast \sqrt{3\ast 2}-\sqrt{3}\ast 4$. By simplifying this, we get $\sqrt{3}(\sqrt{6}-4)=3\sqrt{2}-4\sqrt{3}$
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