Answer
$x=1$
Work Step by Step
$Given,$$\sqrt (2x-1)=x$
Squaring both sides, we get:
$2x-1=x^{2}$
$Thus,(-2x+1)+2x-1=x^{2}+(-2x+1)$
$x^{2}-2x+1=0$
$(x-1)^{2}=0$
$x-1=0$
$x=1$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Lesson Check - Page 623: 3
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