Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Lesson Check: 1

Answer

$x=12$

Work Step by Step

$Given:$ $\sqrt (3x) + 10=16$ $\sqrt (3x) + 10 - 10=$$16-10$ $\sqrt (3x)=6$ $Squaring$ $on$ $both$ $sides,$ $3x=36$ $x=36\div3=12$ $x=12$
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