Chapter 10 - Radical Expressions and Equations - 10-1 The Pythagorean Theorem - Practice and Problem-Solving Exercises - Page 603: 36

120

Step One: $10^{2}$ + $b^{2}$ = $26^{2}$ Step Two: $b^{2}$ = $26^{2}$ - $10^{2}$ Step Three: $b^{2}$ = 576 Step Four: $\sqrt {b^{2}}$ = $\sqrt (576)$ Step Five: b = 24 Step Six: Area of Triangle = (a)(b)/2 = (10)(24)/2 = 120