Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - Chapter Review - 1-2 Order of Operations and Evaluating Expressions - Page 69: 30


a) 216 b) Because the length of the side is squared when computing the area, when the sides are half as long, the area is one-fourth as much. $(\frac{1}{2})^2=\frac{1}{4}$

Work Step by Step

Substitute to find the value. $6s^2=6(6^2)=6(36)=216$ $6s^2=6(3^2)=6(9)=54$ The area is $\frac{1}{4}$ as much when the length of the side is reduced by $\frac{1}{2}$.
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