Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - Chapter Review - 1-2 Order of Operations and Evaluating Expressions - Page 69: 29



Work Step by Step

Substitute the given values and simplify. $(3c^2-3d)^2-21$ $=(3(3^2)-3(5))^2-21$ simplify the exponent in parentheses $=(3(9)-3(5))^2-21$ multiply in parentheses $=(27-15)^2-21$ subtract in parentheses $=12^2-21$ solve exponent $=144-21$ subtract $=123$
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