Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - 1-7 The Distributive Property - Practice and Problem-Solving Exercises - Page 52: 83



Work Step by Step

Find a common factor for each term. That factor can be used as the term that was "distributed across" the difference. 3 is a common factor. Recreate the difference be dividing each term by 3. $3m\div3=m$ $6n\div3=2n$ $15\div3=5$ $3m-6n-15=3(m-2n-5)$
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