Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - 1-4 Properties of Real Numbers - Practice and Problem-Solving Exercises - Page 27: 46

Answer

Not equivalent

Work Step by Step

To simplify this expression, we start by simplifying denominator. $\sqrt 9=3$, so we have $4-8+3=-1$. This gives us $\frac{7t}{-1}$, or $-(\frac{7t}{1})$. This ultimately equals $-7t$. $-7t\ne7t$, so the expressions are not equivalent.
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