## Algebra 1

Published by Prentice Hall

# Chapter 1 - Foundations for Algebra - 1-4 Properties of Real Numbers - Practice and Problem-Solving Exercises - Page 27: 44

Not equivalent

#### Work Step by Step

To simplify this expression, we start by simplifying the numerical part of the fraction. The $\frac{63}{7}$ part of $\frac{63ab}{7a}$ simplifies to $9$, giving $\frac{9ab}{a}$. Finally, the a cancels out because there is one in the numerator and one in the denominator, giving 9b. $9b\ne9ab$.

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