Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Common Core End-of-Course Assessment - Page 797: 48


$\boxed{3x+1}$,$\boxed{2x-5}$ and $\boxed{x^2}$

Work Step by Step

First of all, you must take $x^2$: $x^2(6x^2-13x-5)$ Use Middle-term factoring to factor $6x^2-13x-5$ $6x^2 - 15x + 2x - 5$ $3x(2x-5) +1 (2x-5)$ $(3x+1)(2x-5)$ The dimensions are $\boxed{3x+1}$,$\boxed{2x-5}$ and $\boxed{x^2}$
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